fix: calculate value correctly when P amounts have few decimal digits [#2254]
Valuation in another commoditay could sometimes be inaccurate if the P price amounts did not have enough decimal places.
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@ -48,7 +48,8 @@ import Hledger.Data.Types
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import Hledger.Data.Amount
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import Hledger.Data.Dates (nulldate)
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import Text.Printf (printf)
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import Data.Decimal (decimalPlaces, roundTo)
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import Data.Decimal (decimalPlaces, roundTo, Decimal)
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import Data.Word (Word8)
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------------------------------------------------------------------------------
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@ -290,12 +291,17 @@ priceLookup makepricegraph d from mto =
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-- aggregate all the prices into one
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product rates
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-- product (Decimal's Num instance) normalises, stripping trailing zeros.
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-- Here we undo that (by restoring the old max precision with roundTo),
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-- so that amountValueAtDate can see the original internal precision,
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-- to use as the display precision of calculated value amounts.
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-- (This can add more than the original number of trailing zeros to some prices,
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-- making them seem more precise than they were, but it seems harmless here.)
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& roundTo (maximum $ map decimalPlaces rates)
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-- But we want to preserve even those, since the number of decimal digits
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-- here will guide amountValueAtDate in setting the Amount display precision later.
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-- So we restore them. Or rather, we ensure as many decimal digits as the maximum seen among rates.
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-- (Some prices might end up more precise than they were, but that seems harmless here.)
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& setMinDecimalPlaces (maximum $ map decimalPlaces rates)
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-- Ensure this Decimal has at least this many decimal places, adding trailing zeros if necessary.
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setMinDecimalPlaces :: Word8 -> Decimal -> Decimal
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setMinDecimalPlaces n d
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| decimalPlaces d < n = roundTo n d -- too few, add some zeros
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| otherwise = d -- more than enough, keep as-is
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tests_priceLookup =
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let
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@ -341,3 +341,18 @@ Balance changes in 2019, valued at period ends:
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==========++========
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Assets:A || $2.00
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Income:B || $-2.00
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# ** 33. #2254 Conversion rates should not be display-rounded during value calculation.
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# 100 * 10.5 * 100.5 = 105525
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<
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P 2000-01-01 A 10.5 B
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P 2000-01-01 B 100.5 C
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2000-01-01
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(a) 100 A
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$ hledger -f- print -X C
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2000-01-01
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(a) 105525 C
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>=
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