186 lines
		
	
	
		
			5.9 KiB
		
	
	
	
		
			Haskell
		
	
	
	
	
	
			
		
		
	
	
			186 lines
		
	
	
		
			5.9 KiB
		
	
	
	
		
			Haskell
		
	
	
	
	
	
| {-| 
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| 
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| A ledger-compatible @balance@ command. Here's how it should work:
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| 
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| A sample account tree (as in the sample.ledger file):
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| 
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| @
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|  assets
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|   cash
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|   checking
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|   saving
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|  expenses
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|   food
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|   supplies
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|  income
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|   gifts
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|   salary
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|  liabilities
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|   debts
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| @
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| 
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| The balance command shows top-level accounts by default:
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| 
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| @
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|  \> ledger balance
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|  $-1  assets
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|   $2  expenses
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|  $-2  income
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|   $1  liabilities
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| @
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| 
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| With -s (--showsubs), also show the subaccounts:
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| 
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| @
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|  $-1  assets
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|  $-2    cash
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|   $1    saving
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|   $2  expenses
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|   $1    food
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|   $1    supplies
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|  $-2  income
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|  $-1    gifts
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|  $-1    salary
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|   $1  liabilities:debts
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| @
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| 
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| - @checking@ is not shown because it has a zero balance and no interesting
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|   subaccounts.  
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| 
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| - @liabilities@ is displayed only as a prefix because it has the same balance
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|   as its single subaccount.
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| 
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| With an account pattern, show only the accounts with matching names:
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| 
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| @
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|  \> ledger balance o
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|   $1  expenses:food
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|  $-2  income
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| --------------------
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|  $-1  
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| @
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| 
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| - The o matched @food@ and @income@, so they are shown.
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| 
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| - Parents of matched accounts are also shown for context (@expenses@).
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| 
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| - This time the grand total is also shown, because it is not zero.
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| 
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| Again, -s adds the subaccounts:
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| 
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| @
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| \> ledger -s balance o
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|   $1  expenses:food
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|  $-2  income
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|  $-1    gifts
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|  $-1    salary
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| --------------------
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|  $-1  
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| @
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| 
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| - @food@ has no subaccounts. @income@ has two, so they are shown. 
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| 
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| - We do not add the subaccounts of parents included for context (@expenses@).
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| 
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| Some notes for the implementation:
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| 
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| - a simple balance report shows top-level accounts
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| 
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| - with an account pattern, it shows accounts whose leafname matches, plus their parents
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| 
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| - with the showsubs option, it also shows all subaccounts of the above
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| 
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| - zero-balance leaf accounts are removed
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| 
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| - the resulting account tree is displayed with each account's aggregated
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|   balance, with boring parents prefixed to the next line
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| 
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| - a boring parent has the same balance as its child and is not explicitly
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|   matched by the display options.
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| 
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| - the sum of the balances shown is displayed at the end, if it is non-zero
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| 
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| -}
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| 
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| module BalanceCommand
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| where
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| import Ledger.Utils
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| import Ledger.Types
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| import Ledger.Amount
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| import Ledger.AccountName
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| import Ledger.Ledger
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| import Options
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| import Utils
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| 
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| 
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| -- | Print a balance report.
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| balance :: [Opt] -> [String] -> Ledger -> IO ()
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| balance opts args l = putStr $ showBalanceReport opts args l
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| 
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| -- | Generate balance report output for a ledger, based on options.
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| showBalanceReport :: [Opt] -> [String] -> Ledger -> String
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| showBalanceReport opts args l = acctsstr ++ totalstr
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|     where 
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|       acctsstr = concatMap (showAccountTreeWithBalances acctnamestoshow) $ subs treetoshow
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|       totalstr = if isZeroMixedAmount total 
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|                  then "" 
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|                  else printf "--------------------\n%20s\n" $ showMixedAmount total
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|       showingsubs = ShowSubs `elem` opts
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|       pats@(apats,dpats) = parseAccountDescriptionArgs args
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|       maxdepth = if null args && not showingsubs then 1 else 9999
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|       acctstoshow = balancereportaccts showingsubs apats l
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|       acctnamestoshow = map aname acctstoshow
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|       treetoshow = pruneZeroBalanceLeaves $ pruneUnmatchedAccounts $ treeprune maxdepth $ ledgerAccountTree 9999 l
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|       total = sum $ map abalance $ nonredundantaccts
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|       nonredundantaccts = filter (not . hasparentshowing) acctstoshow
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|       hasparentshowing a = (parentAccountName $ aname a) `elem` acctnamestoshow
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| 
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|       -- select accounts for which we should show balances, based on the options
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|       balancereportaccts :: Bool -> [String] -> Ledger -> [Account]
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|       balancereportaccts False [] l = topAccounts l
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|       balancereportaccts False pats l = accountsMatching pats l
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|       balancereportaccts True pats l = addsubaccts l $ balancereportaccts False pats l
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| 
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|       -- add (in tree order) any missing subacccounts to a list of accounts
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|       addsubaccts :: Ledger -> [Account] -> [Account]
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|       addsubaccts l as = concatMap addsubs as where addsubs = maybe [] flatten . ledgerAccountTreeAt l
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| 
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|       -- remove any accounts from the tree which are not one of the acctstoshow, 
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|       -- or one of their parents, or one of their subaccounts when doing --showsubs
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|       pruneUnmatchedAccounts :: Tree Account -> Tree Account
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|       pruneUnmatchedAccounts = treefilter matched
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|           where 
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|             matched (Account name _ _)
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|                 | name `elem` acctnamestoshow = True
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|                 | any (name `isAccountNamePrefixOf`) acctnamestoshow = True
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|                 | showingsubs && any (`isAccountNamePrefixOf` name) acctnamestoshow = True
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|                 | otherwise = False
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| 
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|       -- remove zero-balance leaf accounts (recursively)
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|       pruneZeroBalanceLeaves :: Tree Account -> Tree Account
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|       pruneZeroBalanceLeaves = treefilter (not . isZeroMixedAmount . abalance)
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| 
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| -- | Show a tree of accounts with balances, for the balance report,
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| -- eliding boring parent accounts. Requires a list of the account names we
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| -- are interested in to help with that.
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| showAccountTreeWithBalances :: [AccountName] -> Tree Account -> String
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| showAccountTreeWithBalances matchednames = 
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|     showAccountTreeWithBalances' matchednames 0 ""
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|     where
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|       showAccountTreeWithBalances' :: [AccountName] -> Int -> String -> Tree Account -> String
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|       showAccountTreeWithBalances' matchednames indent prefix (Node (Account fullname _ bal) subs)
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|           | not isboringparent = this ++ subswithindent
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|           | otherwise = subswithprefix
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|           where
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|             subswithindent = showsubs (indent+1) ""
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|             subswithprefix = showsubs indent (prefix++leafname++":")
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|             showsubs i p = concatMap (showAccountTreeWithBalances' matchednames i p) subs
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|             this = showbal ++ spaces ++ prefix ++ leafname ++ "\n"
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|             showbal = printf "%20s" $ showMixedAmount bal
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|             spaces = "  " ++ replicate (indent * 2) ' '
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|             leafname = accountLeafName fullname
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|             isboringparent = numsubs >= 1 && (bal == subbal || not matched)
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|             numsubs = length subs
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|             subbal = abalance $ root $ head subs
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|             matched = fullname `elem` matchednames
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